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Write a quadratic equation in the variable X. Write in standard form: ax^2+bx+c=0 using 3 as the only solution.

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If there is only one root, it occurs twice:

(x-3)(x-3) = 0
x^2 - 6x + 9 = 0

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The solution is x^2-6x+9=0? In ax^2 + bx + c =0 form? Can you explain please?

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