You left out the numbers
assume p and q
then
(x-p)(x-q) = 0
multiply it out
write a quadratic equation in the variable x having the given numbers as solution. Type the equation in standard form, ax^2+bx+c=0
solution 4, only solution
4 answers
no numbers left out
So what were the given numbers?
Oh, you mean the number 4 is the solution? Then 4 and 4
(x-4)(x-4) = 0
x^2 - 8 x + 16 = 0
(x-4)(x-4) = 0
x^2 - 8 x + 16 = 0