Following my post above.
atomic number on left, element in middle, mass number on right. Left numbers must add up on both side; right numbers must add up on both sides. So for Th we write 90Th234 ==> beta + ?
beta is an electron which is -1e0.
90Th234 ==> -1e0 + AXZ
So 90 = -1 + A and A must be 90 + 1 = 91
234 = 0 + Z so Z must be 234
The element which has atomic number 91 is Pa so the full equation is
90Th234 ==> -1e0 + 91Pa234.
The others are done the same way. I'll be glad to check your answers.
Write a nuclear equation for the indicated decay of each of the following nuclides.
Th−234 (beta)......no clue
O−15 (positron emission): 16/8 O-->16/7N + B+ (said was wrong)
Ar-37: 37/18Ar + e ---> 37/17Cl + v (said was wrong)
what would be the proper equations?
1 answer
2 answers