Write a complete solution to each problem.
If the length of a rectangle is 3 feet longer than the width and
the diagonal I s 15 feet, then what are the length and width?
I do not understand how to solve this problem. Can someone help me?
Thanks.
2 answers
12x9
Use the Pythagorean theorem.
Hypotenuse^2 = sum of squares of other two sides
Let x = length, then width = x - 3
15^2 = x^2 + (x-3)^2
Does this help?
Hypotenuse^2 = sum of squares of other two sides
Let x = length, then width = x - 3
15^2 = x^2 + (x-3)^2
Does this help?
2 answers