Write a balanced chemical equation for the combustion of trioleylglycerol.

Question

The molecular formula is C57H110O6.

Answer 1

the products are CO2 + H2O

C57 h110 O6 + O2 >> 57 CO2 + 55 H2O
now to find the O2: on the right, we have 114+55 O=169O or 84.5 O2
C57 h110 O6 + 84.5O2 >> 57 CO2 + 55 H2O

Now since small minds cannot comprehend non whole numbers in balanced equations (what is exactly the cause of that?)
we double all in the equation.
2C57 h110 O6 + 169O2 >>114 CO2 + 110 H2O

Now check it.