Write 0.4x + 0.2y = 0.6 in slope intercept from

1 answer

To convert the equation \(0.4x + 0.2y = 0.6\) into slope-intercept form, which is \(y = mx + b\) (where \(m\) is the slope and \(b\) is the y-intercept), follow these steps:

  1. Isolate \(y\). Start by moving the term with \(x\) to the other side:

    \[ 0.2y = -0.4x + 0.6 \]

  2. Divide every term by the coefficient of \(y\) (which is 0.2) to solve for \(y\):

    \[ y = \frac{-0.4}{0.2}x + \frac{0.6}{0.2} \]

  3. Simplify the fractions:

    \[ y = -2x + 3 \]

So, the slope-intercept form of the equation \(0.4x + 0.2y = 0.6\) is:

\[ y = -2x + 3 \]