Write 0.4x + 0.2y =0.6 in slope intercept form

Answer 1

To write the equation 0.4x + 0.2y =0.6 in slope-intercept form, we need to isolate y on one side of the equation.

First, let's subtract 0.4x from both sides of the equation:
0.4x + 0.2y - 0.4x = 0.6 - 0.4x.

This simplifies to:
0.2y = -0.4x + 0.6.

Next, let's divide both sides of the equation by 0.2 to solve for y:
(0.2y)/0.2 = (-0.4x + 0.6)/0.2.

This simplifies to:
y = -2x + 3.

Therefore, the equation 0.4x + 0.2y =0.6 can be written in slope-intercept form as y = -2x + 3.

Answer 2

Write the liner equation 3y=6x-18 to slop-intercept form

Answer 3

To write the linear equation 3y = 6x - 18 in slope-intercept form, we need to isolate y on one side of the equation.

First, let's divide both sides of the equation by 3:
(3y)/3 = (6x - 18)/3.

This simplifies to:
y = 2x - 6.

Therefore, the equation 3y = 6x - 18 can be written in slope-intercept form as y = 2x - 6.

Answer 4

What is the slope and the y-intercpt of the equation 9+ 27/2x = - 3/2y write the y-intercept as an ordered pair

Answer 5

To find the slope and y-intercept of the equation 9 + 27/2x = -3/2y, we need to rewrite the equation in slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept.

First, let's simplify the equation:
9 + 27/2x = -3/2y

To isolate y, we can divide both sides of the equation by -3/2:
(9 + 27/2x) / (-3/2) = y

Simplifying further:
y = (-2/3)(9 + 27/2x)

Now, let's distribute -2/3 to (9 + 27/2x):
y = (-2/3)(9) + (-2/3)(27/2x)
y = -6 + (-9x)

So, the slope of the equation is -9 and the y-intercept is -6.

To write the y-intercept as an ordered pair, we have (0, -6).