To write the equation 0.4x + 0.2y = 0.6 in slope-intercept form, we solve for y:
0.4x + 0.2y = 0.6
Subtract 0.4x from both sides:
0.2y = -0.4x + 0.6
Divide both sides by 0.2:
y = -2x + 3
Therefore, the equation in slope-intercept form is y = -2x + 3.
Write 0.4x+0.2y=0.6
in slope-intercept form.(1 point)
y=
9 answers
Write the linear equation 3y=6x−18
in slope-intercept form.(1 point)
in slope-intercept form.(1 point)
To write the equation 3y = 6x - 18 in slope-intercept form, we solve for y:
3y = 6x - 18
Divide both sides by 3:
y = 2x - 6
Therefore, the equation in slope-intercept form is y = 2x - 6.
3y = 6x - 18
Divide both sides by 3:
y = 2x - 6
Therefore, the equation in slope-intercept form is y = 2x - 6.
What is the slope and the y
-intercept of the equation 9+272x=−32y
. Write the y
-intercept as an ordered pair.(1 point)
The slope is
. The y
-intercept is (
).
-intercept of the equation 9+272x=−32y
. Write the y
-intercept as an ordered pair.(1 point)
The slope is
. The y
-intercept is (
).
To find the slope and the y-intercept of the equation 9 + 272x = -32y, we need to rewrite the equation in slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept.
9 + 272x = -32y
Divide both sides by -32 to isolate y:
y = (-272/32)x - (9/32)
Simplify:
y = -17x - (9/32)
The slope is -17 and the y-intercept is (0, -9/32).
9 + 272x = -32y
Divide both sides by -32 to isolate y:
y = (-272/32)x - (9/32)
Simplify:
y = -17x - (9/32)
The slope is -17 and the y-intercept is (0, -9/32).
wrong
Apologies for the mistake.
To find the slope and the y-intercept of the equation 9 + 272x = -32y, we need to rewrite the equation in slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept.
Starting with the given equation:
9 + 272x = -32y
First, divide both sides by -32 to isolate y:
y = (-272/32)x - (9/32)
Simplify:
y = -17x - (9/32)
Comparing with the slope-intercept form, we see that the slope is -17 and the y-intercept is (0, -9/32).
To find the slope and the y-intercept of the equation 9 + 272x = -32y, we need to rewrite the equation in slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept.
Starting with the given equation:
9 + 272x = -32y
First, divide both sides by -32 to isolate y:
y = (-272/32)x - (9/32)
Simplify:
y = -17x - (9/32)
Comparing with the slope-intercept form, we see that the slope is -17 and the y-intercept is (0, -9/32).
Use the image to answer the question.
An illustration shows a coordinate plane with four quadrants. The x and y axes range from negative 10 to 10 in one unit increments. A downward slanting line is graphed on the coordinate plane. The downward slanting line passes through closed points plotted at left parenthesis 0 comma 10 right parenthesis and left parenthesis 1 comma 7 right parenthesis.
Annie has created a graph of 3x+y=10
on the coordinate plane. Did Annie create her graph correctly?
Option 1: No; Annie's y
-intercept is correct but her slope is incorrect.
Option 2: No; Annie's slope is correct but her y
-intercept is incorrect.
Option 3: Yes; Annie's graph is correct.
Enter "1" for Option 1, "2" for Option 2, or "3" for Option 3.
(1 point)
Option
An illustration shows a coordinate plane with four quadrants. The x and y axes range from negative 10 to 10 in one unit increments. A downward slanting line is graphed on the coordinate plane. The downward slanting line passes through closed points plotted at left parenthesis 0 comma 10 right parenthesis and left parenthesis 1 comma 7 right parenthesis.
Annie has created a graph of 3x+y=10
on the coordinate plane. Did Annie create her graph correctly?
Option 1: No; Annie's y
-intercept is correct but her slope is incorrect.
Option 2: No; Annie's slope is correct but her y
-intercept is incorrect.
Option 3: Yes; Annie's graph is correct.
Enter "1" for Option 1, "2" for Option 2, or "3" for Option 3.
(1 point)
Option
To determine if Annie created her graph correctly, we can compare her equation, 3x + y = 10, to the given points (0,10) and (1,7).
Substituting the first point (0,10) into her equation, we get:
3(0) + y = 10
y = 10
This matches the y-intercept of the given line.
Substituting the second point (1,7) into her equation, we get:
3(1) + y = 10
3 + y = 10
y = 7
This also matches the y-coordinate of the given line.
Therefore, Annie's graph is correct.
Option 3: Yes; Annie's graph is correct.
Substituting the first point (0,10) into her equation, we get:
3(0) + y = 10
y = 10
This matches the y-intercept of the given line.
Substituting the second point (1,7) into her equation, we get:
3(1) + y = 10
3 + y = 10
y = 7
This also matches the y-coordinate of the given line.
Therefore, Annie's graph is correct.
Option 3: Yes; Annie's graph is correct.