Writ the equation in Logarithm form

25=(1/5)^2
a=b^c

2 answers

Logb(a) = c

Log1/5(25) = 2
but 25 is not (1/5)^2
(1/5)^2 = 1/25
25 = 1/(1/5)^2 = (1/5)^-2
So, log1/525 = -2

loga = c*logb
regardless of base. Using b for the base, log_b(b)=1,so
logba = c