Wouldn't it be 3*0.234 instead of 2* 0.234? since....2Al3+ +3SO4 2- ----> Al2(SO4)3

Question

4.) A solution is prepared by dissolving 25.0 g of aluminum sulfate in enough water to make 125.0 mL of stock solution. A 10.0 mL aliquot (portion) of this stock solution is then removed and added to 15.0 mL of water. Calculate the concentrations of all ions in the final solution.

My answer:

[Al2(SO4)3]= 0.234M

[Al3+]= 0.468M

[SO4 2-]= 0.702M

I would have use 0.2338 x 2 = 0.0701 for SO4^2-. The others look ok.

Answer 1

Of course, that's the only way to get 0.701. You should check all of these closely, especially for typos. My eyesight is not all that good. I did proof each answer before posting but sometimes I miss them the second time through.