The numerator and denominator of the fraction can be factored and common (x-3) factors canceled to give
(x^2 + 3x +9)/(x+3)
When x = 3, that fraction is 27/6 = 9/2
You can also use L'Hopital's rule to get the same answer.
Your answer is correct.
Would the limit of lim x-->3 (x^3 -27)/(x^2 -9) be:
9/2?
1 answer
1 answer