No. Ga is atomic number 31 The electron configuration for the neutral element is 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p1 = 31 So you remove the last three electrons in the outside shell to make Ga^3+. That will be removing 4s2 and 4p1.
[Ar] 3d10 = Ga^3+
Yes, I KNOW that 4s2 fills BEFORE 3d fills. BUT the 4s shell still is the outside shell and when making the ion it's the 4s and 4p electrons that come off. That is true for Cu^+ , Cu^2+, Zn^2+, Ga^3+ etc. After the 4s shell is filled to make it 4s2, at that point the 3d orbitals are lower in energy than the 4s so making ions is done by removing the 4s electrons first.
Would the electron configuration of Ga+3 be 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^8, and it's noble gas electron configuration would be [Ar] 4s^2 3d^8?
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