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would one consider the molecule NBr3O to be nonpolar or polar? I feel like all of the dipole moments will cancel, when you draw the VSPER structure the Br atom in the plane and out of the plane cancel, however O going up and the Br coming out of the plane, ...I feel like the Br would have a greater pull, but maybe insignificant. I know NBr3 would be polar due to the lone pair on N.

sorry to repost haha I'd hate to get this wrong

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