To determine which equation represents the slope of the line passing through the points (0, 1) and (1, 4), we need to find the slope of the line first.
The slope \( m \) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is calculated using the formula:
\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
Substituting the given points (0, 1) and (1, 4):
\[ m = \frac{4 - 1}{1 - 0} = \frac{3}{1} = 3 \]
Now that we have the slope, we can use the point-slope form of the equation of a line, which is:
\[ y - y_1 = m(x - x_1) \]
Using point (0, 1):
\[ y - 1 = 3(x - 0) \]
Simplifying this gives:
\[ y - 1 = 3x \quad \Rightarrow \quad y = 3x + 1 \]
Now, let's verify the two equations provided:
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The equation \( -5x - y = -1 \) can be rewritten as: \[ -y = 5x - 1 \quad \Rightarrow \quad y = -5x + 1 \]
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The equation \( y = -5x + 1 \) is already in slope-intercept form.
From our calculations, we found that the slope of the line is 3 with y-intercept 1, resulting in \( y = 3x + 1 \). The two equations you provided, \( y = -5x + 1 \) and \( -5x - y = -1 \) both have a slope of -5, which does not match the slope we calculated.
Thus, neither \( -5x - y = -1 \) nor \( y = -5x + 1 \) is correct for the line through the points (0, 1) and (1, 4). The correct equation based on the points given is:
\[ y = 3x + 1 \]