wjhat is the substitutional consequence of life
A. sus
B. dont be sus
C. sus?
D. we so sussy
3 answers
plz help
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The stem-and-leaf plot shows the heights in centimeters of Teddy Bear sunflowers grown in two different types of soil.
Soil A Soil B
5 9
5 2 1 1 6 3 9
5 1 0 7 0 2 3 6 7 8
2 1 8 3
0 9
Key: 9|6 means 69 Key: 5|8 means 58
Calculate the mean of each data set.
Calculate the mean absolute deviation (MAD) of each data set.
Which set is more variable? How do you know?
The stem-and-leaf plot shows the heights in centimeters of Teddy Bear sunflowers grown in two different types of soil.
Soil A Soil B
5 9
5 2 1 1 6 3 9
5 1 0 7 0 2 3 6 7 8
2 1 8 3
0 9
Key: 9|6 means 69 Key: 5|8 means 58
Calculate the mean of each data set.
Calculate the mean absolute deviation (MAD) of each data set.
Which set is more variable? How do you know?
Mean of Soil A:
- We have 14 data points in Soil A.
- Adding all the heights in Soil A, we get: 50 + 51 + 51 + 52 + 55 + 57 + 58 + 59 + 59 + 60 + 61 + 71 + 78 + 90 = 745
- Dividing the sum by the number of data points, we get: 745/14 ≈ 53.21
Mean of Soil B:
- We have 15 data points in Soil B.
- Adding all the heights in Soil B, we get: 30 + 32 + 33 + 36 + 37 + 38 + 39 + 60 + 63 + 67 + 69 + 70 + 72 + 73 + 79 = 821
- Dividing the sum by the number of data points, we get: 821/15 ≈ 54.73
To calculate the MAD of each data set:
- Find the absolute deviation of each data point from the mean. Absolute deviation is simply the absolute value of the difference between the data point and the mean.
- Find the mean of these absolute deviations.
Mean absolute deviation of Soil A:
- Absolute deviations from the mean:
|50 - 53.21| = 3.21
|51 - 53.21| = 2.21
|51 - 53.21| = 2.21
|52 - 53.21| = 1.21
|55 - 53.21| = 1.79
|57 - 53.21| = 3.79
|58 - 53.21| = 4.79
|59 - 53.21| = 5.79
|59 - 53.21| = 5.79
|60 - 53.21| = 6.79
|61 - 53.21| = 7.79
|71 - 53.21| = 17.79
|78 - 53.21| = 24.79
|90 - 53.21| = 36.79
- Mean of absolute deviations: (3.21 + 2.21 + 2.21 + 1.21 + 1.79 + 3.79 + 4.79 + 5.79 + 5.79 + 6.79 + 7.79 + 17.79 + 24.79 + 36.79)/14 ≈ 8.76
Mean absolute deviation of Soil B:
- Absolute deviations from the mean:
|30 - 54.73| = 24.73
|32 - 54.73| = 22.73
|33 - 54.73| = 21.73
|36 - 54.73| = 18.73
|37 - 54.73| = 17.73
|38 - 54.73| = 16.73
|39 - 54.73| = 15.73
|60 - 54.73| = 5.27
|63 - 54.73| = 8.27
|67 - 54.73| = 12.27
|69 - 54.73| = 14.27
|70 - 54.73| = 15.27
|72 - 54.73| = 17.27
|73 - 54.73| = 18.27
|79 - 54.73| = 24.27
- Mean of absolute deviations: (24.73 + 22.73 + 21.73 + 18.73 + 17.73 + 16.73 + 15.73 + 5.27 + 8.27 + 12.27 + 14.27 + 15.27 + 17.27 + 18.27 + 24.27)/15 ≈ 16.03
Soil B is more variable than Soil A because its mean absolute deviation is larger. This indicates that the data points in Soil B are more spread out from the mean compared to Soil A.
- We have 14 data points in Soil A.
- Adding all the heights in Soil A, we get: 50 + 51 + 51 + 52 + 55 + 57 + 58 + 59 + 59 + 60 + 61 + 71 + 78 + 90 = 745
- Dividing the sum by the number of data points, we get: 745/14 ≈ 53.21
Mean of Soil B:
- We have 15 data points in Soil B.
- Adding all the heights in Soil B, we get: 30 + 32 + 33 + 36 + 37 + 38 + 39 + 60 + 63 + 67 + 69 + 70 + 72 + 73 + 79 = 821
- Dividing the sum by the number of data points, we get: 821/15 ≈ 54.73
To calculate the MAD of each data set:
- Find the absolute deviation of each data point from the mean. Absolute deviation is simply the absolute value of the difference between the data point and the mean.
- Find the mean of these absolute deviations.
Mean absolute deviation of Soil A:
- Absolute deviations from the mean:
|50 - 53.21| = 3.21
|51 - 53.21| = 2.21
|51 - 53.21| = 2.21
|52 - 53.21| = 1.21
|55 - 53.21| = 1.79
|57 - 53.21| = 3.79
|58 - 53.21| = 4.79
|59 - 53.21| = 5.79
|59 - 53.21| = 5.79
|60 - 53.21| = 6.79
|61 - 53.21| = 7.79
|71 - 53.21| = 17.79
|78 - 53.21| = 24.79
|90 - 53.21| = 36.79
- Mean of absolute deviations: (3.21 + 2.21 + 2.21 + 1.21 + 1.79 + 3.79 + 4.79 + 5.79 + 5.79 + 6.79 + 7.79 + 17.79 + 24.79 + 36.79)/14 ≈ 8.76
Mean absolute deviation of Soil B:
- Absolute deviations from the mean:
|30 - 54.73| = 24.73
|32 - 54.73| = 22.73
|33 - 54.73| = 21.73
|36 - 54.73| = 18.73
|37 - 54.73| = 17.73
|38 - 54.73| = 16.73
|39 - 54.73| = 15.73
|60 - 54.73| = 5.27
|63 - 54.73| = 8.27
|67 - 54.73| = 12.27
|69 - 54.73| = 14.27
|70 - 54.73| = 15.27
|72 - 54.73| = 17.27
|73 - 54.73| = 18.27
|79 - 54.73| = 24.27
- Mean of absolute deviations: (24.73 + 22.73 + 21.73 + 18.73 + 17.73 + 16.73 + 15.73 + 5.27 + 8.27 + 12.27 + 14.27 + 15.27 + 17.27 + 18.27 + 24.27)/15 ≈ 16.03
Soil B is more variable than Soil A because its mean absolute deviation is larger. This indicates that the data points in Soil B are more spread out from the mean compared to Soil A.