To determine whether the product of \(\sqrt{49}\) and \(\frac{1}{3}\) is rational or irrational, we first evaluate \(\sqrt{49}\).
\(\sqrt{49} = 7\), which is a rational number.
Now we consider the product:
\[\sqrt{49} \times \frac{1}{3} = 7 \times \frac{1}{3} = \frac{7}{3}.\]
Since \(\frac{7}{3}\) is a fraction of two integers, it is a rational number.
Therefore, the product is rational.
So the answer is 1 for rational.