With the aid of an equation explainthe dissociation of salt both strong and weak alkali and acid

Answer 1

Dissociation of salts, strong acids, and strong bases can be explained using the following chemical equation:

1. Dissociation of salt (NaCl) in water:
NaCl (s) → Na+ (aq) + Cl- (aq)

2. Dissociation of a strong acid (HCl) in water:
HCl (aq) → H+ (aq) + Cl- (aq)

3. Dissociation of a strong base (NaOH) in water:
NaOH (aq) → Na+ (aq) + OH- (aq)

For weak acids and weak bases, the dissociation equilibrium equation can be written as follows:

1. Dissociation of acetic acid (CH3COOH) in water:
CH3COOH (aq) + H2O (l) ⇌ CH3COO- (aq) + H3O+ (aq)

2. Dissociation of ammonia (NH3) in water:
NH3 (aq) + H2O (l) ⇌ NH4+ (aq) + OH- (aq)

In these equations, the double arrow (⇌) represents the reversible nature of the dissociation reaction, where the reactants can form products and vice versa. The dissociation of weak acids and weak bases is influenced by the equilibrium constant, which determines the extent of dissociation in the solution.