Initial speed = 98 km/h = 98/3.6 m/s
Work done
= KE(final)-KE(initial)
= (1/2)1370(0²-(98/3.6)²)
= -508 kJ (approx.)
With brakes fully applied, a 1370 kg car deccelerates from a speed of 98.0 km/hr. What is the work done by the braking force in bringing the car to a stop?
1 answer