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With a platinum catalyst, ammonia will burn in oxygen to give nitric oxide, NO. 4NH3 + 5O2 -----> 4NO + 6H2O Delta H= -906 kJ W...Asked by Glenna
With a platinum catalyst, ammonia will burn in oxygen to give nitric oxide, NO.
4 NH3(g) + 5 O2(g) 4 NO(g) + 6 H2O(g) ÄH = -906 kJ
What is the enthalpy change for the following reaction?
NO(g) + 3/2 H2O(g) NH3(g) + 5/4 O2(g)
4 NH3(g) + 5 O2(g) 4 NO(g) + 6 H2O(g) ÄH = -906 kJ
What is the enthalpy change for the following reaction?
NO(g) + 3/2 H2O(g) NH3(g) + 5/4 O2(g)
Answers
Answered by
drwls
I assume that ÄH is supposed to be "delta H"
Note that the second reaction is the reverse of the first, but with the number of moles reacting 4 times less.
That should give you a pretty good hint of what the answer is.
Note that the second reaction is the reverse of the first, but with the number of moles reacting 4 times less.
That should give you a pretty good hint of what the answer is.
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