To determine whether a precipitate will form in the given reaction, we need to analyze the solubility of the products formed.
The reaction is: \[ \text{CaI}_2 + \text{Fe(NO}_3)_2 \rightarrow \text{Ca(NO}_3)_2 + \text{FeI}_2 \]
- Calcium Nitrate (Ca(NO3)2): This salt is soluble in water.
- Iron(II) Iodide (FeI2): Generally, iodides are soluble, but FeI2 is one of the exceptions and can precipitate under certain conditions.
Thus, in this reaction, the potential precipitate is FeI2, assuming concentrations are such that it exceeds its solubility.
Conclusion: Yes, \(\text{FeI}_2\) will precipitate.