this has been answered already. Reiny just stated that since x^2 is always positive, there's no real value of x which can produce -7 when squared.
Damon actually wrote the quadratic in standard form, applied the formula and gave the complex solutions.
http://www.jiskha.com/display.cgi?id=1399935086
Just what is it that is still bothering you?
Will someone explain how to solve this?
Write each equation in standard form. Solve by using the Quadratic Formula.
1. -7 = x^2
2 answers
1. -7 = X^2
x^2 + 7 = 0
X =( -B +- sqrt(B^2-4AC))/2A
X = (0 +- sqrt(0-28))/2 =
sqrt(28*(-1))/2 = 5.29i/2 = +-2.65i
x^2 + 7 = 0
X =( -B +- sqrt(B^2-4AC))/2A
X = (0 +- sqrt(0-28))/2 =
sqrt(28*(-1))/2 = 5.29i/2 = +-2.65i
3 answers