Why would you subtract the heat capacity of the calorimeter when calculating the heat of the reaction?

Answer 1

In an enthalpy experiment
total heat = (mass H2O x specific heat H2O x delta T) + Ccal x (delta T)
I may misunderstand the question but I don't think you subtract the heat capacity of the calorimeter.

Answer 2

I think that the question is saying why you do subtraction in the equation Qrxn=-Qcal-Qsoln