Why is my actual percent of sulfate in alum a lot less than my theoretical percent of sulfate in alum?
Actual Percent SO4= 1.68%
Theoretical Percent SO4= 40.5%
4 answers
I don't know without seeing all of your work. One possibility is that you lost some of the BaSO4 ppt. A second possibility is that you didn't ppt all of the sulfate in the sample due to the conditions; i.e., pH not right, not adding enough BaCl2, etc. Your calculations could be wrong.
Well the questions are confusing, the first question asks to find the mass of sulfate in my 1 gram sample of alum based off of the mass of BaSO4 (0.52g).
The second question then asks to calculate the percent sulfate in my alum, and I don't know if that means my sample of alum or the total mass of alum the reaction produced which was 11.28.
The second question then asks to calculate the percent sulfate in my alum, and I don't know if that means my sample of alum or the total mass of alum the reaction produced which was 11.28.
I think the first question is % SO4 in your 1 grams sample.
That is 0.52 x (molar mass SO4/molar mass BaSO4)*100 = about 21% (The mass is about 0.21g)
I think the second question is to calculate the theoretical percent SO4 in your 1 g sample (or any mass sample) so you can compare your experimental value with the theoretical value.
The theoretical % SO4 in alum is about 40%. (96.064*2/474.39)*100 = ?
That is 0.52 x (molar mass SO4/molar mass BaSO4)*100 = about 21% (The mass is about 0.21g)
I think the second question is to calculate the theoretical percent SO4 in your 1 g sample (or any mass sample) so you can compare your experimental value with the theoretical value.
The theoretical % SO4 in alum is about 40%. (96.064*2/474.39)*100 = ?
That sounds right to me..thanks for all of your help.
3 answers