Why is ln(e^-2) = -2.
Why doesn't it = e^-2??
6 answers
ln (e^x) = x ln e = x * 1 = x
so what if it was ln5(e^-2). would the answer be -10?? thanks for your help:)
No, it is only because ln is base e that ln(e^x) = x
in general
loga (a^x) = x loga(a) = x*1 = x
log 5 of 5 is 1, but log5 (e) is not one
in general
loga (a^x) = x loga(a) = x*1 = x
log 5 of 5 is 1, but log5 (e) is not one
okay thanks
it is all because
b^logb (x) = x
so
5^log5 (5) = 5
so log5 (5) has to be 1
b^logb (x) = x
so
5^log5 (5) = 5
so log5 (5) has to be 1
thanks damon!!!!!!
3 answers