why is it that when an unknown carbonate of group one or two (inc H) reacting w/ HCl, the mole ratio is 1:1

Answer 1

Could you be talking about half neutralizing Na2CO3? If completely neutralized, it is a ratio of 1:2.
Na2CO3 + 2HCl ==> 2NaCl + H2O + CO2
CaCO3 + 2HCl ==> CaCl2 + H2O + CO2.

If half neutralized, then
Na2CO3 + HCl ==> NaHCO3 + NaCl.

Answer 2

Not just Na
I mean all group 1 and 2 elements

Answer 3

Li2CO3
Na2CO3
K2CO3
Rb2CO3
Cs2CO3
All the same.
Group I is group I. They all go through the same reaction, at least with HCl.