2F^- --> F2 + 2e -2.87
2I^- ==> I2 + 2e -0.535
But somehow I don't think this is the answer your are looking for. As to WHY the potentials are that way-- I suppose that's the nature of the beast. F^- being such a small ion isn't likely to give up electrons. Those electrons on I^- are farther out because of the size and more easily given up.
Why is I- a stronger reducing agent than F-?
2 answers
Interesting. Thank you.