The statement "The book and the table both have acceleration (due to gravity) of 9.8 m/s/s" is incorrect. Both the book and the table are at rest, which means their acceleration is zero.
When a book is resting on a table, it is in a state of equilibrium because the forces acting on it are balanced. In this case, we have two forces acting on the book: its weight (the force of gravity pulling it downward) and the upward force exerted by the table.
According to Newton's third law of motion, the weight of the book and the upward force exerted by the table have equal magnitude but opposite directions. This means that the force of gravity pulling the book downward is balanced by the upward force exerted by the table. As a result, there is no unbalanced force acting on the book, and it remains in a state of equilibrium, or at rest.
Additionally, it is correct that the book and the table have the same weight. The weight of an object is the force of gravity acting on it and is determined by its mass and the acceleration due to gravity. Since the book and the table are at rest on Earth's surface, they experience the same acceleration due to gravity. Therefore, their weights are equal.
Why is a book resting on a table in a state of equilibrium?
The book and the table both have acceleration (due to gravity) of 9.8 m/s/s.
The book’s weight and the upward force the table exerts on the book have equal magnitude but opposing directions.
Gravity is a net force acting on the book in a downward direction
The book and the table have the same weight.
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