Why does the calculator make the last number 8 even though it’s 7 repeating?

1 answer

It sounds like you're dealing with a situation involving rounding or approximating a repeating decimal. When a number is expressed as 7 with a repeating decimal (7.777...), it can be mathematically expressed as:

\[ 7.777... = 7 + 0.777... \]

The repeating portion 0.777... can be shown to equal \( \frac{7}{9} \), making the total equal to:

\[ 7 + \frac{7}{9} = \frac{63}{9} + \frac{7}{9} = \frac{70}{9} \approx 7.777... \]

If you're using a calculator that rounds numbers, it could be approximating this number to the nearest whole number. In many cases, when rounding, a decimal of 0.5 or higher rounds up, while a decimal below 0.5 rounds down. If we consider 7.777... as roughly 8 when rounded to the nearest integer, that would explain why it's being displayed as 8 on your calculator.

If this doesn’t specifically address your situation, please provide more context about how you're inputting the number or the calculations involved, and I can provide more precise clarification!

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