Asked by big145
Why do the graphs of reciprocals of linear functions always have vertical asymptotes, but the graphs of reciprocals of quadratic functions sometimes do not? Justify with an example.
Answers
Answered by
oobleck
except for horizontal lines, there is a point where y=0
The reciprocal would have you divide by zero, which is undefined.
Some quadratic functions, such as y = x^2+1 are never zero, so 1/y is always defined.
The reciprocal would have you divide by zero, which is undefined.
Some quadratic functions, such as y = x^2+1 are never zero, so 1/y is always defined.
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