Asked by layla lomax
                While using the Zero Product Property to find the solutions for the quadratic equation  (x−2)(x−9)=0, a student completed the work below.  Is the student's work correct?
(x−2)(x−9)=0
original equation
 
Solution #1:
x−2=0
 
x=2
 
 
Solution #2:
x+9=0
 
x=−9
 
 
(1 point)
Responses
No, there should be a solution #3.
No, there should be a solution #3.
No, x−9=0
should have been used to find solution #2.
No, x minus 9 is equal to 0 should have been used to find solution #2.
Yes, the student answered the problem correctly.
Yes, the student answered the problem correctly.
No, x+2=0
should have been used to find solution #1.
No, x plus 2 is equal to 0 should have been used to find solution #1.
            
        (x−2)(x−9)=0
original equation
Solution #1:
x−2=0
x=2
Solution #2:
x+9=0
x=−9
(1 point)
Responses
No, there should be a solution #3.
No, there should be a solution #3.
No, x−9=0
should have been used to find solution #2.
No, x minus 9 is equal to 0 should have been used to find solution #2.
Yes, the student answered the problem correctly.
Yes, the student answered the problem correctly.
No, x+2=0
should have been used to find solution #1.
No, x plus 2 is equal to 0 should have been used to find solution #1.
Answers
                                                    There are no human answers yet.
                                            
                
                    Answered by
            GPT-4o mini
            
    The student’s work is not correct. Here’s what went wrong:
In the solution #2 step, the student incorrectly set up the equation to find the second solution. Instead of solving \( x + 9 = 0 \), the student should have used \( x - 9 = 0 \).
The correct steps should be:
1. From \( (x - 2)(x - 9) = 0 \), set each factor equal to zero:
- \( x - 2 = 0 \) leads to \( x = 2 \) (this solution is correct)
- \( x - 9 = 0 \) leads to \( x = 9 \) (this solution was missed)
Therefore, the correct conclusion is:
**No, there should be a solution #3.**
    
In the solution #2 step, the student incorrectly set up the equation to find the second solution. Instead of solving \( x + 9 = 0 \), the student should have used \( x - 9 = 0 \).
The correct steps should be:
1. From \( (x - 2)(x - 9) = 0 \), set each factor equal to zero:
- \( x - 2 = 0 \) leads to \( x = 2 \) (this solution is correct)
- \( x - 9 = 0 \) leads to \( x = 9 \) (this solution was missed)
Therefore, the correct conclusion is:
**No, there should be a solution #3.**
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