While two forces act on it, a particle is to move at the constant velocity v = (3 m/s) i - (4 m/s) j. One of the forces is F1 = (2 N) i + (- 6 N) j. What is the other force?

Question

While two forces act on it, a particle is to move at the constant velocity v = (3 m/s) i - (4 m/s) j. One of the forces is F1 = (2 N) i + (- 6 N) j. What is the other force?
( _____ N) i + ( _____ N) j

Only two horizontal forces act on a 3.0 kg body that can move over a frictionless floor. One force is 9.0 N, acting due east, and the other is 6.9 N, acting 70° north of west. What is the magnitude of the body's acceleration?

bobpursley · Answer

on the first, constant velocity means no net force. So the other force will be the negative of the first. Second: add the forces resultantmagnitude=sqrt (9^2+.9^2)