While on vacation, Kevin went for a swim in a nearby lake. Swimming against the current, it took him 8 minutes to swim 200 meters. Swimming back to shore with the current took half as long. Find Kevin's average swimming speed and the speed of the lake's cuurent.

Answer 1

Let the speed of the current be y m/min
let Kevin's rate of swimming be x m/min

against the current: 8(x-y) = 200
with the current : 4(x+y) = 200

from the first 8x - 8y = 200 reduced to
x-y = 25

from the second equation x + y = 50

add them: 2x = 75
x = 37.5 m/min

subbing back in the second
y = 12.5

So the lake's current was 12.5 m/min
and his rate of swimming in still water would be 37.5 m/min

Answer 2

I NEED HELP IN CONVERTING 33/50 INTO A DECIMAL

Answer 3

Cheyenne -- please click Post a New Question and ask ask your question.

Answer 4

yoyoyo