To determine when the rock hits the water, we need to find when the height \( h \) is 0 (i.e., when the rock reaches the surface of the lake). Thus, we can set up the equation:
\[ -4.9t^2 + 10 = 0 \]
This simplifies to:
\[ 4.9t^2 = 10 \] \[ t^2 = \frac{10}{4.9} \] \[ t^2 \approx 2.04 \] \[ t \approx \sqrt{2.04} \approx 1.43 \text{ seconds} \]
Since the time until the rock hits the water is approximately 1.43 seconds, we can set up a table for \( t \) with reasonable increments.
Given these options:
- 5
- 2
- 10
- 110
- 1 tenth
A reasonable scale for the range, considering the time until impact is around 1.43 seconds, would be 2 seconds. This allows for a manageable table that covers from 0 to at least 2 seconds.