X = 6.3 m.
Y = 36.6 m.
A. D^2 = X^2 + Y^2.
D^2 = (6.3)^2 + (36.6)^2 = 1379.25
D = 37.1 m.
B. tanA = Y/X = 36.6/6.3 = 5.80952
A = 80.2o, CCW.
A = 90 - 80.2 = 9.8o, East of North.
While following the directions on a treasure map, a pirate walks 36.6 m north, then turns and walks 6.3 m east.
A.) What is the magnitude of the single straight-line displacement that the pirate could have taken to reach the treasure? Answer in units of m. *The answer to A.) is 36.8 meters.
B.)At what angle with the north would he have to walk? Answer in units of ◦ (degrees)
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2 answers