First, let's find the mass of the drop of blood.
Mass = 0.800 g = 0.0008 kg
(b) Now, we can find the force exerted by the blood vessel on the drop of blood using F = ma.
F = (0.0008 kg)(1.54 m/s²) = 0.001232 N
(c) When the arm is not swinging, the only force acting on the drop of blood is gravity. To find the force, we can use F = mg.
F = (0.0008 kg)(9.8 m/s²) = 0.00784 N
While a person is walking, his arms swing through approximately a 45° angle in .530s. As a reasonable approximation, we can assume that the arm moves with constant speed during each swing. A typical arm is 70.0 cm long, measured from the shoulder joint. (a) What is the acceleration of a .800 gram drop of blood in the fingertips at the bottom of the swing?
1.54m/s^s i got correct
(b) Find the force that the blood vessel must exert on the drop of blood in part a.
im having touble solving this problem and part c
(c) What force would the blood vessel exert if the arm were not swinging?
i know the formula i use is F=ma
1 answer