Which value of x is a solution to this equation?%0D%0A%0D%0A%0D%0A%0D%0A8x2−2x−3=0

Answer 1

To find the values of x that are solutions to the equation 8x^2 - 2x - 3 = 0, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / 2a

In this equation, a = 8, b = -2, and c = -3.

Plugging in these values, we get:

x = (2 ± √((-2)^2 - 4*8*(-3))) / 2*8
x = (2 ± √(4 + 96)) / 16
x = (2 ± √100) / 16
x = (2 ± 10) / 16

This gives us two possible solutions:

x = (2 + 10) / 16 = 12 / 16 = 3/4
x = (2 - 10) / 16 = -8 / 16 = -1/2

Therefore, the values of x that are solutions to the equation 8x^2 - 2x - 3 = 0 are x = 3/4 and x = -1/2.