Which value of x is a solution to this equation? 8x^2−2x−3=0

Answer 1

To find the solution for the equation 8x^2 - 2x - 3 = 0, we can use the quadratic formula x = (-b ± √(b^2 - 4ac)) / 2a.

In this case, a = 8, b = -2, and c = -3.

Plugging these values into the formula:

x = (2 ± √((-2)^2 - 4 * 8 * -3)) / 2 * 8
x = (2 ± √(4 + 96)) / 16
x = (2 ± √100) / 16
x = (2 ± 10) / 16

So, the two solutions are:

x = (2 + 10) / 16 = 12 / 16 = 3/4
x = (2 - 10) / 16 = -8 / 16 = -1/2

Therefore, the values of x that are solutions to the equation are x = 3/4 and x = -1/2.

Answer 2

options are a. 8 b. -0.5 c. -3 d. 4.5

Answer 3

The correct solutions are x = 3/4 and x = -1/2.

Therefore, none of the options provided (a. 8, b. -0.5, c. -3, d. 4.5) are solutions to the equation 8x^2 - 2x - 3 = 0.