which value of k makes p^2-8p+k a perfect square?

1 answer

let, p^2-8p+k =0
then,we have to find two numbers whose sum is -8 and product is k and then by solving the equation, we will get 0. so,such numbers are -4 and-4
by expanding the equation, we have
p^2 (-4-4)p +(-4×-4)=0
p^2 -4p -4p +16=0
p(p-4) -4(p-4)=0
(p-4) (p-4)=0
p-4=0
p=4
by putting the value of p in equation, we have
=(4^2) -(8×4) +(16)
=(16) -(32) +(16)
=32-32
=0.
so,the value of k is 16.
Similar Questions
  1. Which numbers are perfect squares?A) 64 b)900 c)120 d)1000 e)100 F) 10 000 How do u know each number is a perfect square? A)
    1. answers icon 4 answers
  2. x^2- 18x = -80A. Suppose the equivalent equation is written x^2 -18x +c= -80+ c. What value of c makes the equation a perfect
    1. answers icon 1 answer
  3. what is a perfect square number i know 9, 25 and 100, but what elseif you multiply a perfect square by a perfect square, is the
    1. answers icon 1 answer
    1. answers icon 1 answer
more similar questions