Which value is equivalent to the complex number i Superscript 26 Baseline?

Answer options with 4 options
A.
i

B.
negative i

C.
1

D.
negative 1

1 answer

To find the value of \( i^{26} \), we can use the property of powers of \( i \) (the imaginary unit). The powers of \( i \) cycle every 4:

\[ \begin{align*} i^1 & = i \ i^2 & = -1 \ i^3 & = -i \ i^4 & = 1 \ \end{align*} \]

After \( i^4 \), the pattern repeats: \( i^5 = i \), \( i^6 = -1 \), \( i^7 = -i \), and so on.

To simplify \( i^{26} \), we can find the remainder when 26 is divided by 4:

\[ 26 \div 4 = 6 \quad \text{(remainder 2)} \]

This means:

\[ 26 = 4 \times 6 + 2 \]

Thus, \( i^{26} \) corresponds to \( i^2 \):

\[ i^{26} = i^2 = -1 \]

Therefore, the value equivalent to the complex number \( i^{26} \) is:

\[ \boxed{-1} \]