To determine which two consecutive whole numbers \(\sqrt{39}\) lies between, we need to find the perfect squares that are closest to 39.
- \(5^2 = 25\)
- \(6^2 = 36\)
- \(7^2 = 49\)
Now we observe that:
- \(36 < 39 < 49\)
This indicates that \(\sqrt{39}\) lies between \(6\) (since \(\sqrt{36} = 6\)) and \(7\) (since \(\sqrt{49} = 7\)).
Thus, the correct answer is that \(\sqrt{39}\) lies between 6 and 7 because \(39\) falls between \(6^2 = 36\) and \(7^2 = 49\).