Which table shows the results of the reflection of the function over the x-axis

On graph (-2,2),(-3,3),(-1,3),(-4,4),(-5,5),(-6,6), (0,4),(1,5),(2,6)
Table 1
x y
-4 4
-3 3
-2 2
-1 3
0 4
1 5
Table 2
x y
-4 -4
-3 -3
-2 -2
-1 -3
0 -4
1 -5
Table 3
x y
4 -4
3 -3
2 -2
1 -3
0 -4
-1 -5
Table 4
x y
4 4
3 3
2 2
1 3
0 4
-1 5

1 answer

To reflect a set of points over the x-axis, the y-coordinates of each point must be inverted (i.e., multiplied by -1), while the x-coordinates remain unchanged.

Given the original points:

  • (-2, 2)
  • (-3, 3)
  • (-1, 3)
  • (-4, 4)
  • (-5, 5)
  • (-6, 6)
  • (0, 4)
  • (1, 5)
  • (2, 6)

Applying the reflection over the x-axis, we will calculate the new points:

  • (-2, 2) → (-2, -2)
  • (-3, 3) → (-3, -3)
  • (-1, 3) → (-1, -3)
  • (-4, 4) → (-4, -4)
  • (-5, 5) → (-5, -5)
  • (-6, 6) → (-6, -6)
  • (0, 4) → (0, -4)
  • (1, 5) → (1, -5)
  • (2, 6) → (2, -6)

Now, let's check the tables:

  • Table 1:
x          y
-4         4
-3         3
-2         2 
-1         3
0          4
1          5

(This table does not show reflected values.)

  • Table 2:
x         y
-4       -4
-3       -3
-2       -2
-1       -3
0        -4
1        -5

(This table shows the correct reflected values for points -4, -3, -2, -1, and 0, but does not include all original values or their reflected pairs.)

  • Table 3:
x        y
4       -4
3       -3
2       -2
1       -3
0      -4
-1      -5

(This table shows values that do not correspond to the reflection of the original points correctly.)

  • Table 4:
x        y
4       4
3       3 
2       2
1       3
0       4
-1      5

(This table does not show reflected values.)

Based on the calculation above, none of the provided tables accurately represent the reflection of the original points over the x-axis. However, Table 2 closely resembles some of the reflected values.

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