To determine the approximate value of the square root of 28, we can compare it to the squares of whole numbers.
- The square of 5 is \(5^2 = 25\).
- The square of 6 is \(6^2 = 36\).
Since \(28\) is between \(25\) and \(36\), it follows that:
\[ 5 < \sqrt{28} < 6 \]
Next, we can check how close \(\sqrt{28}\) is to \(5\) and \(6\). Since \(28\) is closer to \(25\) than \(36\), \(\sqrt{28}\) will be closer to \(5\).
To find a more precise approximation:
- If we compute \(\sqrt{28}\), we find it is approximately \(5.2915\).
This confirms that \(\sqrt{28}\) is indeed between \(5\) and \(6\), and closer to \(5\).
Therefore, the correct statement is:
It is between 5 and 6, probably closer to 5.