To determine the approximate value of the square root of 28, we can compare it to perfect squares:
- \(5^2 = 25\)
- \(6^2 = 36\)
Since \(25 < 28 < 36\), we know that \(5 < \sqrt{28} < 6\).
To further narrow it down, we can calculate the squares of numbers between 5 and 6:
- \(5.2^2 = 27.04\)
- \(5.3^2 = 28.09\)
Since \(27.04 < 28 < 28.09\), it follows that \(5.2 < \sqrt{28} < 5.3\).
Thus, we can conclude that the square root of 28 is between 5 and 6, and it is closer to 6.
So the true statement is:
It is between 5 and 6, probably closer to 6.