To determine the square root of 28, we can find the perfect squares around it.
- The square of 5 is \(5^2 = 25\).
- The square of 6 is \(6^2 = 36\).
Since 28 is between 25 and 36, we know that:
\[ 5 < \sqrt{28} < 6 \]
Next, we can approximate \(\sqrt{28}\). Since 28 is closer to 25 than to 36, we would expect \(\sqrt{28}\) to be closer to 5 than to 6.
To calculate it more accurately, we can recognize that:
\[ \sqrt{28} = \sqrt{4 \times 7} = 2\sqrt{7} \]
Approximating \(\sqrt{7}\), we know that:
- \(2.6^2 = 6.76\),
- \(2.7^2 = 7.29\).
Thus, \(2.6 < \sqrt{7} < 2.7\), which gives:
\[ 5.2 < 2\sqrt{7} < 5.4. \]
Therefore, we can conclude that \(\sqrt{28}\) is between 5 and 6, and we expect it to be closer to 5.
Thus, the correct statement is:
"It is between 5 and 6, probably closer to 5."