Which statement correctly defines dynamic equilibrium?
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Dynamic equilibrium refers to a situation in which the rate of the forward reaction is equal to the rate of the reverse reaction, leading to a constant concentration of both reactants and products.
Which statement correctly defines dynamic equilibrium? (1 point)%0D%0AResponses%0D%0A%0D%0AForces acting on a object are balanced and the object stays in rest.%0D%0AForces acting on a object are balanced and the object stays in rest.%0D%0A%0D%0AForces acting on a object are unbalanced and the object stays in rest.%0D%0AForces acting on a object are unbalanced and the object stays in rest.%0D%0A%0D%0AForces acting on a object are balanced and the object stays in motion.
The statement that correctly defines dynamic equilibrium is: "Forces acting on an object are balanced and the object stays in motion."
While you push a box you begin to decrease the force you are exerting on the box. When will the box reach static equilibrium?
The box will reach static equilibrium when the force you are exerting on it becomes equal to the opposing force of friction. At this point, the box will come to rest and there will be no net force acting on it.
What is the fastest motion that can be measured in any frame of reference?
The fastest motion that can be measured in any frame of reference is the speed of light in a vacuum, which is approximately 299,792,458 meters per second (or about 186,282 miles per second). According to the theory of relativity, the speed of light is constant and is the maximum speed at which any information or object can travel in the universe.
Two people are on a train that is moving at 10 m/s north. They are walking 1 m/s south relative to the train. Relative to the ground, their motion is 9 m/s north.
That is not correct. When two people are on a train that is moving at 10 m/s north and they are walking 1 m/s south relative to the train, their motion relative to the ground would be the vector sum of their velocities. The person's velocity relative to the ground would be the velocity of the train (10 m/s north) minus their relative velocity to the train (1 m/s south). Therefore, the correct relative motion of the two people to the ground would be 9 m/s north, not south.
A student holds a water balloon outside of an open window and lets go. The window is 10 meters above the ground, and the balloon is falling under the acceleration of gravity, which is 9.8 m/s2. If t = 1 sec, what is the distance? Use the formula x = xo + vot + ½(at2)
To find the distance traveled by the water balloon after 1 second of falling, we can use the formula x = xo + vot + ½(at²).
In this case:
- xo is the initial position of the water balloon, which is 10 meters (height of the window above the ground).
- vo is the initial velocity of the water balloon, which is 0 m/s as it is initially at rest.
- a is the acceleration of the water balloon due to gravity, which is -9.8 m/s² (negative since it acts in the opposite direction).
- t is the time, provided as 1 second.
Plugging these values into the formula, we have:
x = 10 + 0(1) + ½(-9.8)(1²)
x = 10 - 4.9
x = 5.1 meters
Therefore, after 1 second of falling, the water balloon will have traveled a distance of 5.1 meters.
In this case:
- xo is the initial position of the water balloon, which is 10 meters (height of the window above the ground).
- vo is the initial velocity of the water balloon, which is 0 m/s as it is initially at rest.
- a is the acceleration of the water balloon due to gravity, which is -9.8 m/s² (negative since it acts in the opposite direction).
- t is the time, provided as 1 second.
Plugging these values into the formula, we have:
x = 10 + 0(1) + ½(-9.8)(1²)
x = 10 - 4.9
x = 5.1 meters
Therefore, after 1 second of falling, the water balloon will have traveled a distance of 5.1 meters.
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