Which statement best

describes alpha decay?
(1 point)
After the ejection of
an alpha particle, the
remaining nucleus
has a mass number
that is four less and
an atomic number
that is two less, so
alpha decay is not a
type of nuclear
fission.
After the ejection of
an alpha particle, the
remaining nucleus
has a mass number
that is four less and
an atomic number
that is two less, so
alpha decay is a
type of nuclear
fission.
After the ejection of
an alpha particle, the
remaining nucleus
has a mass number
that is two less and
an atomic number
that is two less, so
alpha decay is a
type of nuclear
fission.
After the ejection of
an alpha particle, the

1 answer

The statement that best describes alpha decay is:

"After the ejection of an alpha particle, the remaining nucleus has a mass number that is four less and an atomic number that is two less, so alpha decay is not a type of nuclear fission."

Alpha decay involves the emission of an alpha particle, which consists of 2 protons and 2 neutrons (essentially a helium nucleus). This results in the original nucleus losing 4 units in mass number (2 protons + 2 neutrons) and 2 units in atomic number (2 protons). Furthermore, alpha decay is distinct from nuclear fission, which involves the splitting of a heavier nucleus into smaller nuclei, often accompanied by the release of energy.