To determine the effect on the parabola represented by the equations \( y = x^2 + 4x \) and \( y = x^2 + 6x \), we can rewrite each equation in vertex form.
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For \( y = x^2 + 4x \):
We complete the square: \[ y = (x^2 + 4x) = (x^2 + 4x + 4) - 4 = (x + 2)^2 - 4 \] The vertex is at the point \((-2, -4)\).
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For \( y = x^2 + 6x \):
Again, we complete the square: \[ y = (x^2 + 6x) = (x^2 + 6x + 9) - 9 = (x + 3)^2 - 9 \] The vertex is at the point \((-3, -9)\).
Now we compare the vertices of the two parabolas.
- The first parabola has a vertex at \((-2, -4)\), and the second parabola has a vertex at \((-3, -9)\).
From \((-2, -4)\) to \((-3, -9)\):
- The horizontal shift is from \(-2\) to \(-3\), which is a shift to the left by \(1\) unit.
- The vertical shift is from \(-4\) to \(-9\), which is a shift downward by \(5\) units.
Thus, the correct statement is: D. The parabola is shifted down 5 units and to the left 1 unit.