The statement "The function nx=5x2−20x+12 has a minimum value of -8" is true.
To determine this, we need to first find the vertex of the function. The vertex of a quadratic function in the form ax^2 + bx + c can be found using the formula x = -b/(2a). In this case, a = 5 and b = -20, so the x-coordinate of the vertex is x = -(-20)/(2*5) = 2.
Plugging this x-coordinate back into the function, we can find the y-coordinate of the vertex. n(2) = 5(2)^2 - 20(2) + 12 = 8 - 40 + 12 = -20.
Therefore, the function has a minimum value of -20 at the vertex (2, -20).
Which statement about the function nx=5x2−20x+12is true?
HINT: Graph the function in your calculator to determine domain and range.
1 answer
1 answer