Which situation is best represented by the following equation?
20h+40=480
(1 point)
Responses
Stacey was paid $40 last week. She was paid a $20 bonus and $480 for each hour she worked.
Stacey was paid $40 last week. She was paid a $20 bonus and $480 for each hour she worked.
Stacey was paid $480 last week. She was paid a $40 bonus and $20 for each hour she worked.
Stacey was paid $480 last week. She was paid a $40 bonus and $20 for each hour she worked.
Stacey was paid $480 last week. She was paid a $20 bonus and $40 for each hour she worked.
Stacey was paid $480 last week. She was paid a $20 bonus and $40 for each hour she worked.
Stacey was paid $40 last week. She was paid a $480 bonus and $20 for each hour she worked.
Stacey was paid $40 last week. She was paid a $480 bonus and $20 for each hour she worked.
38 answers
Stacey was paid $480 last week. She was paid a $20 bonus and $40 for each hour she worked.
Which situation is best represented by the following equation?
2000−200x=1000
(1 point)
Responses
Jenny went on vacation. She started with $2000 and spent $200 each day. Solve for x to find the number of days Jenny has been on vacation if she has $1000 left to spend.
Jenny went on vacation. She started with $2000 and spent $200 each day. Solve for x to find the number of days Jenny has been on vacation if she has $1000 left to spend.
Jenny went on vacation. She started with $2000 and spent $200 each day. Solve for x to find out how much money Jenny has left to spend.
Jenny went on vacation. She started with $2000 and spent $200 each day. Solve for x to find out how much money Jenny has left to spend.
Jenny went on vacation. She spent $200 each day. Solve for x to find the number of days Jenny has been on vacation if she has $1000 left to spend.
Jenny went on vacation. She spent $200 each day. Solve for x to find the number of days Jenny has been on vacation if she has $1000 left to spend.
Jenny went on vacation. She started with $1000 and spent $250 each day. Solve for x to find the number of days Jenny has been on vacation if she has $2000 left to spend.
2000−200x=1000
(1 point)
Responses
Jenny went on vacation. She started with $2000 and spent $200 each day. Solve for x to find the number of days Jenny has been on vacation if she has $1000 left to spend.
Jenny went on vacation. She started with $2000 and spent $200 each day. Solve for x to find the number of days Jenny has been on vacation if she has $1000 left to spend.
Jenny went on vacation. She started with $2000 and spent $200 each day. Solve for x to find out how much money Jenny has left to spend.
Jenny went on vacation. She started with $2000 and spent $200 each day. Solve for x to find out how much money Jenny has left to spend.
Jenny went on vacation. She spent $200 each day. Solve for x to find the number of days Jenny has been on vacation if she has $1000 left to spend.
Jenny went on vacation. She spent $200 each day. Solve for x to find the number of days Jenny has been on vacation if she has $1000 left to spend.
Jenny went on vacation. She started with $1000 and spent $250 each day. Solve for x to find the number of days Jenny has been on vacation if she has $2000 left to spend.
The situation best represented by the equation 2000-200x=1000 is:
Jenny went on vacation. She started with $2000 and spent $200 each day. Solve for x to find the number of days Jenny has been on vacation if she has $1000 left to spend.
Jenny went on vacation. She started with $2000 and spent $200 each day. Solve for x to find the number of days Jenny has been on vacation if she has $1000 left to spend.
Jillian spent $31 to park for 6 hours. The parking garage charges a base rate of $3 for the first two 2 hours, and then an hourly rate for each additional hour. How much does each additional hour of parking cost?(1 point)
Responses
$8.50
$8.50
$5.17
$5.17
$4.67
$4.67
$7.00
Responses
$8.50
$8.50
$5.17
$5.17
$4.67
$4.67
$7.00
To determine the cost of each additional hour of parking, we need to subtract the cost of the base rate from the total cost and divide the result by the number of additional hours.
The total cost of parking for 6 hours is $31.
The base rate for the first 2 hours is $3.
The cost of the additional 4 hours is $31 - $3 = $28.
To find the cost for each additional hour, we divide $28 by the number of additional hours, which is 4.
$28 / 4 = $7
Therefore, the cost of each additional hour of parking is $7.
The total cost of parking for 6 hours is $31.
The base rate for the first 2 hours is $3.
The cost of the additional 4 hours is $31 - $3 = $28.
To find the cost for each additional hour, we divide $28 by the number of additional hours, which is 4.
$28 / 4 = $7
Therefore, the cost of each additional hour of parking is $7.
Daisy has 6 more than three times as many seashells as Lucy. Daisy has 36 seashells. How many does Lucy have?(1 point)
Responses
14
14
90
90
10
10
126
Responses
14
14
90
90
10
10
126
To find out how many seashells Lucy has, we need to consider that Daisy has 6 more than three times as many seashells as Lucy.
Let's represent the number of seashells Lucy has by L.
According to the given information, Daisy has 6 more than three times Lucy's number of seashells, so we can write this equation:
3L + 6 = 36
Now, we need to solve this equation to find the value of L.
Subtract 6 from both sides:
3L = 36 - 6
3L = 30
Divide both sides by 3:
L = 30 / 3
L = 10
Therefore, Lucy has 10 seashells.
Let's represent the number of seashells Lucy has by L.
According to the given information, Daisy has 6 more than three times Lucy's number of seashells, so we can write this equation:
3L + 6 = 36
Now, we need to solve this equation to find the value of L.
Subtract 6 from both sides:
3L = 36 - 6
3L = 30
Divide both sides by 3:
L = 30 / 3
L = 10
Therefore, Lucy has 10 seashells.
Solve for c.
2/5c+5=95
(1 point)
Responses
225
225
36
36
250
250
40
2/5c+5=95
(1 point)
Responses
225
225
36
36
250
250
40
To solve for c, we need to isolate the variable c on one side of the equation.
The given equation is:
2/5c + 5 = 95
To get rid of the constant term on the left side of the equation, we can subtract 5 from both sides:
2/5c = 95 - 5
2/5c = 90
Next, we want to eliminate the fraction by multiplying both sides by the reciprocal of 2/5, which is 5/2:
(5/2)(2/5c) = (5/2)(90)
(cancellation)
1c = 225
Therefore, the solution for c is 225.
The given equation is:
2/5c + 5 = 95
To get rid of the constant term on the left side of the equation, we can subtract 5 from both sides:
2/5c = 95 - 5
2/5c = 90
Next, we want to eliminate the fraction by multiplying both sides by the reciprocal of 2/5, which is 5/2:
(5/2)(2/5c) = (5/2)(90)
(cancellation)
1c = 225
Therefore, the solution for c is 225.
What value for n makes this equation true?
13−2n=−109
(1 point)
Responses
-61
-61
-48
-48
48
48
61
61
13−2n=−109
(1 point)
Responses
-61
-61
-48
-48
48
48
61
61
To solve for n, we need to isolate the variable n on one side of the equation.
The given equation is:
13 - 2n = -109
To isolate the variable, we can first subtract 13 from both sides of the equation:
-2n = -109 - 13
-2n = -122
Next, we want to solve for n by dividing both sides by -2:
(-2n) / -2 = (-122) / -2
(n) = 61
Therefore, the value of n that makes the equation true is 61.
The given equation is:
13 - 2n = -109
To isolate the variable, we can first subtract 13 from both sides of the equation:
-2n = -109 - 13
-2n = -122
Next, we want to solve for n by dividing both sides by -2:
(-2n) / -2 = (-122) / -2
(n) = 61
Therefore, the value of n that makes the equation true is 61.
Three hundred students went on a field trip to the zoo. Six buses were filled and 12 students rode in cars. How many students were on each bus?(1 point)
Responses
48
48
52
52
62
62
288
Responses
48
48
52
52
62
62
288
To calculate the number of students on each bus, we first need to subtract the students who rode in cars from the total number of students:
Total students - Students in cars = Students on buses
300 - 12 = 288
Now, we divide the number of students on buses by the number of buses to find the number of students on each bus:
288 / 6 = 48
Therefore, there were 48 students on each bus.
Total students - Students in cars = Students on buses
300 - 12 = 288
Now, we divide the number of students on buses by the number of buses to find the number of students on each bus:
288 / 6 = 48
Therefore, there were 48 students on each bus.
Clara wants to bike 112 miles this week. That is 20 miles less than 2 times the number of miles she biked last week. How many miles did she bike last week?(1 point)
Responses
46 miles
46 miles
132 miles
132 miles
264 miles
264 miles
66 miles
Responses
46 miles
46 miles
132 miles
132 miles
264 miles
264 miles
66 miles
To find out how many miles Clara biked last week, we need to solve the equation.
Let's represent the number of miles she biked last week as "x."
According to the given information, Clara wants to bike 112 miles this week, which is 20 miles less than twice the number of miles she biked last week.
We can write this equation:
2x - 20 = 112
Let's solve this equation to find the value of x.
Add 20 to both sides:
2x = 112 + 20
2x = 132
Divide both sides by 2:
x = 132 / 2
x = 66
Therefore, Clara biked 66 miles last week.
Let's represent the number of miles she biked last week as "x."
According to the given information, Clara wants to bike 112 miles this week, which is 20 miles less than twice the number of miles she biked last week.
We can write this equation:
2x - 20 = 112
Let's solve this equation to find the value of x.
Add 20 to both sides:
2x = 112 + 20
2x = 132
Divide both sides by 2:
x = 132 / 2
x = 66
Therefore, Clara biked 66 miles last week.
Solve for m.
−7m=42
(1 point)
Responses
49
49
35
35
6
6
-6
−7m=42
(1 point)
Responses
49
49
35
35
6
6
-6
To solve for m, we need to isolate the variable m on one side of the equation.
The given equation is:
-7m = 42
To isolate m, we divide both sides of the equation by -7:
-7m / -7 = 42 / -7
m = -6
Therefore, the solution for m is -6.
The given equation is:
-7m = 42
To isolate m, we divide both sides of the equation by -7:
-7m / -7 = 42 / -7
m = -6
Therefore, the solution for m is -6.
Solve for k.
k−2=−10
(1 point)
Responses
5
5
20
20
-5
-5
-20
k−2=−10
(1 point)
Responses
5
5
20
20
-5
-5
-20
To solve for k, we need to isolate the variable k on one side of the equation.
The given equation is:
k - 2 = -10
To isolate k, we can add 2 to both sides of the equation:
k - 2 + 2 = -10 + 2
k = -8
Therefore, the solution for k is -8.
The given equation is:
k - 2 = -10
To isolate k, we can add 2 to both sides of the equation:
k - 2 + 2 = -10 + 2
k = -8
Therefore, the solution for k is -8.
nope
Apologies for the incorrect response.
To solve for k, we need to isolate the variable k on one side of the equation.
Given equation: k - 2 = -10
To isolate k, we can add 2 to both sides of the equation:
k - 2 + 2 = -10 + 2
k = -8
But it seems that the provided response is not correct. Let's try again:
k - 2 = -10
To isolate k, we need to undo the subtraction by adding 2 to both sides of the equation:
k - 2 + 2 = -10 + 2
k = -8
Therefore, the solution for k is -8.
To solve for k, we need to isolate the variable k on one side of the equation.
Given equation: k - 2 = -10
To isolate k, we can add 2 to both sides of the equation:
k - 2 + 2 = -10 + 2
k = -8
But it seems that the provided response is not correct. Let's try again:
k - 2 = -10
To isolate k, we need to undo the subtraction by adding 2 to both sides of the equation:
k - 2 + 2 = -10 + 2
k = -8
Therefore, the solution for k is -8.
Solve for k.
k/−2=−10
(1 point)
Responses
5
5
20
20
-5
-5
-20
k/−2=−10
(1 point)
Responses
5
5
20
20
-5
-5
-20
To solve for k, we need to isolate the variable k on one side of the equation.
The given equation is:
k / -2 = -10
To isolate k, we can multiply both sides of the equation by -2:
(k / -2) * -2 = -10 * -2
This simplifies to:
k = 20
Therefore, the solution for k is 20.
The given equation is:
k / -2 = -10
To isolate k, we can multiply both sides of the equation by -2:
(k / -2) * -2 = -10 * -2
This simplifies to:
k = 20
Therefore, the solution for k is 20.
Solve for y.
5y−10=−25
(1 point)
Responses
3
3
-3
-3
7
7
-7
-7
5y−10=−25
(1 point)
Responses
3
3
-3
-3
7
7
-7
-7
To solve for y, we need to isolate the variable y on one side of the equation.
The given equation is:
5y - 10 = -25
To isolate y, we can add 10 to both sides of the equation:
5y - 10 + 10 = -25 + 10
This simplifies to:
5y = -15
Next, we divide both sides of the equation by 5:
(5y) / 5 = (-15) / 5
This simplifies to:
y = -3
Therefore, the solution for y is -3.
The given equation is:
5y - 10 = -25
To isolate y, we can add 10 to both sides of the equation:
5y - 10 + 10 = -25 + 10
This simplifies to:
5y = -15
Next, we divide both sides of the equation by 5:
(5y) / 5 = (-15) / 5
This simplifies to:
y = -3
Therefore, the solution for y is -3.
Solve for x.
−3x+4=−8
(1 point)
Responses
43
4 thirds
-4
-4
4
4
−43
−3x+4=−8
(1 point)
Responses
43
4 thirds
-4
-4
4
4
−43
To solve for x, we need to isolate the variable x on one side of the equation.
The given equation is:
-3x + 4 = -8
To isolate x, we can subtract 4 from both sides of the equation:
-3x + 4 - 4 = -8 - 4
This simplifies to:
-3x = -12
Next, we divide both sides of the equation by -3:
(-3x) / -3 = (-12) / -3
This simplifies to:
x = 4
Therefore, the solution for x is 4.
The given equation is:
-3x + 4 = -8
To isolate x, we can subtract 4 from both sides of the equation:
-3x + 4 - 4 = -8 - 4
This simplifies to:
-3x = -12
Next, we divide both sides of the equation by -3:
(-3x) / -3 = (-12) / -3
This simplifies to:
x = 4
Therefore, the solution for x is 4.
Solve for w.
−0.1w+23.2=−0.8
(1 point)
Responses
-224
-224
-240
-240
240
240
224
−0.1w+23.2=−0.8
(1 point)
Responses
-224
-224
-240
-240
240
240
224
To solve for w, we need to isolate the variable w on one side of the equation.
The given equation is:
-0.1w + 23.2 = -0.8
To isolate w, we can subtract 23.2 from both sides of the equation:
-0.1w + 23.2 - 23.2 = -0.8 - 23.2
This simplifies to:
-0.1w = -24
Next, we divide both sides of the equation by -0.1:
(-0.1w) / -0.1 = (-24) / -0.1
This simplifies to:
w = 240
Therefore, the solution for w is 240.
The given equation is:
-0.1w + 23.2 = -0.8
To isolate w, we can subtract 23.2 from both sides of the equation:
-0.1w + 23.2 - 23.2 = -0.8 - 23.2
This simplifies to:
-0.1w = -24
Next, we divide both sides of the equation by -0.1:
(-0.1w) / -0.1 = (-24) / -0.1
This simplifies to:
w = 240
Therefore, the solution for w is 240.
What is the first operation used in solving this equation?
m/10−12=−24
(1 point)
Responses
subtraction
subtraction
multiplication
multiplication
addition
addition
division
division
m/10−12=−24
(1 point)
Responses
subtraction
subtraction
multiplication
multiplication
addition
addition
division
division
The first operation used in solving the equation m/10 - 12 = -24 is subtraction. It is used to subtract 12 from m/10 in order to isolate the term m/10.
Cody has 22 rare coins. Each year Clark plans to add 15 coins to his collection. How many years will it take Cody to collect 577 coins?(1 point)
Responses
40 years
40 years
37 years
37 years
27 years
27 years
25 years
Responses
40 years
40 years
37 years
37 years
27 years
27 years
25 years
To determine how many years it will take Cody to collect 577 coins, we can set up an equation based on the given information.
Let's represent the number of years it will take Cody to collect the coins as "y."
According to the given information, each year, Clark plans to add 15 coins to his collection, and Cody currently has 22 rare coins.
The total number of coins collected after y years can be represented by the equation:
22 + 15y = 577
To solve this equation for y, we need to isolate the variable y.
First, we subtract 22 from both sides of the equation:
15y = 577 - 22
15y = 555
Next, we divide both sides of the equation by 15:
y = 555 / 15
y = 37
Therefore, it will take Cody 37 years to collect 577 coins.
Let's represent the number of years it will take Cody to collect the coins as "y."
According to the given information, each year, Clark plans to add 15 coins to his collection, and Cody currently has 22 rare coins.
The total number of coins collected after y years can be represented by the equation:
22 + 15y = 577
To solve this equation for y, we need to isolate the variable y.
First, we subtract 22 from both sides of the equation:
15y = 577 - 22
15y = 555
Next, we divide both sides of the equation by 15:
y = 555 / 15
y = 37
Therefore, it will take Cody 37 years to collect 577 coins.
Tom is given the equation 10x+15=20
to solve. He says the solution is 1/2
. Which reason justifies his solution?(1 point)
Responses
Tom says that to solve the equation you first divide by 10 and then subtract 15.
Tom says that to solve the equation you first divide by 10 and then subtract 15.
Tom says that to solve the equation you first subtract 15 and then multiply by 10.
Tom says that to solve the equation you first subtract 15 and then multiply by 10.
Tom says that to solve the equation you first add 15 and then divide by 10.
Tom says that to solve the equation you first add 15 and then divide by 10.
Tom says that to solve the equation you first subtract 15 and then divide by 10.
to solve. He says the solution is 1/2
. Which reason justifies his solution?(1 point)
Responses
Tom says that to solve the equation you first divide by 10 and then subtract 15.
Tom says that to solve the equation you first divide by 10 and then subtract 15.
Tom says that to solve the equation you first subtract 15 and then multiply by 10.
Tom says that to solve the equation you first subtract 15 and then multiply by 10.
Tom says that to solve the equation you first add 15 and then divide by 10.
Tom says that to solve the equation you first add 15 and then divide by 10.
Tom says that to solve the equation you first subtract 15 and then divide by 10.
Tom says that to solve the equation, you first subtract 15 and then divide by 10.
This reasoning is incorrect. To solve the equation 10x + 15 = 20, we need to isolate the variable x.
First, we subtract 15 from both sides of the equation:
10x + 15 - 15 = 20 - 15
10x = 5
Next, we divide both sides of the equation by 10:
(10x) / 10 = 5 / 10
x = 1/2
Therefore, the correct solution for the equation 10x + 15 = 20 is x = 1/2.
This reasoning is incorrect. To solve the equation 10x + 15 = 20, we need to isolate the variable x.
First, we subtract 15 from both sides of the equation:
10x + 15 - 15 = 20 - 15
10x = 5
Next, we divide both sides of the equation by 10:
(10x) / 10 = 5 / 10
x = 1/2
Therefore, the correct solution for the equation 10x + 15 = 20 is x = 1/2.
a b c d
I apologize, but it is not clear what you are referring to with the letters a, b, c, and d. Could you please provide more context or clarify your question?
Tom is given the equation 10x+15=20
to solve. He says the solution is 12
. Which reason justifies his solution?(1 point) a b c d
Responses
Tom says that to solve the equation you first divide by 10 and then subtract 15.
Tom says that to solve the equation you first divide by 10 and then subtract 15.
Tom says that to solve the equation you first subtract 15 and then multiply by 10.
Tom says that to solve the equation you first subtract 15 and then multiply by 10.
Tom says that to solve the equation you first add 15 and then divide by 10.
Tom says that to solve the equation you first add 15 and then divide by 10.
Tom says that to solve the equation you first subtract 15 and then divide by 10.
to solve. He says the solution is 12
. Which reason justifies his solution?(1 point) a b c d
Responses
Tom says that to solve the equation you first divide by 10 and then subtract 15.
Tom says that to solve the equation you first divide by 10 and then subtract 15.
Tom says that to solve the equation you first subtract 15 and then multiply by 10.
Tom says that to solve the equation you first subtract 15 and then multiply by 10.
Tom says that to solve the equation you first add 15 and then divide by 10.
Tom says that to solve the equation you first add 15 and then divide by 10.
Tom says that to solve the equation you first subtract 15 and then divide by 10.