Which shows the graph of x – 4y =–4?

A coordinate plane with a line passing through (0, negative 4) and (1, 0).
A coordinate plane with a line passing through (negative 4, negative 2), (0, negative 1) and (4, 0).
A coordinate plane with a line passing through (negative 2, negative 4), (negative 1, 0) and (0, 4).
A coordinate plane with a line passing through (negative 4, 0) and (0, 1).

1 answer

To determine which graph represents the equation \( x - 4y = -4 \), we can rearrange this equation into slope-intercept form \( y = mx + b \).

Starting with the given equation:

\[ x - 4y = -4 \]

We can isolate \( y \) as follows:

  1. Subtract \( x \) from both sides:

\[ -4y = -x - 4 \]

  1. Divide each term by \(-4\):

\[ y = \frac{1}{4}x + 1 \]

Now we can identify the slope and y-intercept from this:

  • The slope (\( m \)) is \( \frac{1}{4} \),
  • The y-intercept (\( b \)) is \( 1 \).

Using the slope and the y-intercept, we can find a couple of points on the graph of the line.

  • The y-intercept indicates that when \( x = 0 \), \( y = 1 \). So, one point is \( (0, 1) \).
  • To find another point, let’s use the x-intercept. Set \( y = 0 \):

\[ 0 = \frac{1}{4}x + 1 \ \frac{1}{4}x = -1 \ x = -4 \]

So, another point is \( (-4, 0) \).

Now we have two points: \( (0, 1) \) and \( (-4, 0) \).

Now, let's evaluate the options:

  1. A coordinate plane with a line passing through \( (0, -4) \) and \( (1, 0) \) — does not match.
  2. A coordinate plane with a line passing through \( (-4, -2) \), \( (0, -1) \), and \( (4, 0) \) — does not match.
  3. A coordinate plane with a line passing through \( (-2, -4) \), \( (-1, 0) \), and \( (0, 4) \) — does not match.
  4. A coordinate plane with a line passing through \( (-4, 0) \) and \( (0, 1) \) — matches.

Thus, the correct choice is the last option, which represents the line for the equation \( x - 4y = -4 \).

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